A) 22 km/sec
B) 11 km/sec
C) 5.5 km/sec
D) 15.5 km/sec
Correct Answer: A
Solution :
\[{{v}_{e}}=\sqrt{\frac{2GM}{R}}=R\sqrt{\frac{8}{3}\pi G\rho }\]\\[{{v}_{e}}\propto R\] if r = constant Since the planet having double radius in comparison to earth therefore the escape velocity becomes twice i.e. 22 km/s.
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