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JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Gravitation Potential

  • question_answer
    A body of mass m is placed on the earth?s surface. It is taken from the earth?s surface to a height \[h=3R\]. The change in gravitational potential energy of the body is [CBSE PMT 2002]

    A)             \[\frac{2}{3}mgR\]

    B)               \[\frac{3}{4}mgR\]

    C)             \[\frac{mgR}{2}\]      

    D)             \[\frac{mgR}{4}\]

    Correct Answer: B

    Solution :

                    \[\Delta U=\frac{mgh}{1+\frac{h}{R}}=\frac{mg\times 3R}{1+\frac{3R}{R}}=\frac{3}{4}mgR\]


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