question_answer

A body is released from certain height and falls freely towards the earth. Exactly 1s later another body is released. Distance between the two bodies 2s after the release of the second body is (a) 4.9 m                              (b) 9.8 m (c) 24.5 m                            (d) 50 m

Answer:

\[h=ut+\frac{1}{2}{{t}^{2}}\]for ?1? falling body \[{{h}_{1}}=\frac{1}{2}\times 10\times {{2}^{2}}=20m\] \[{{h}_{2}}=\frac{1}{2}\times 10\times 9=45m\] \[{{h}_{2}}{{h}_{1}}=4520=25\text{ }m\]