Answer:
\[{{T}^{2}}\propto {{R}^{3}}\]\[\Rightarrow \]\[T\propto {{R}^{3/2}}\] \[\Rightarrow \]\[\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{R_{2}^{3/2}}{R_{1}^{3/2}}={{\left( \frac{{{R}_{2}}}{{{R}_{1}}} \right)}^{3/2}}={{\left( \frac{R}{4R} \right)}^{3/2}}\] \[\frac{{{T}_{2}}}{1}=\frac{1}{{{4}^{3/2}}}=\frac{1}{{{({{2}^{2}})}^{3/2}}}=\frac{1}{8}\] \[\therefore \]\[{{T}_{2}}=\frac{1}{8}\]of the present year. \[{{R}_{1}}=R\] \[{{T}_{1}}=1\text{ }year\] \[{{R}_{2}}=R/4\] \[{{T}_{2}}=?\]
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