A) h/2
B) h/4
C) 3h/4
D) Depends upon mass and volume of ball.
Correct Answer: C
Solution :
\[h=\frac{1}{2}g{{t}^{2}}\] In\[\frac{T}{2}\]sec the distance travelled is\[\frac{1}{2}g{{\left( \frac{T}{2} \right)}^{2}}=\frac{h}{4}\] position of the ball from the ground is \[h-\frac{h}{4}=\frac{3h}{4}\]
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