question_answer

g at height\[h=\frac{R}{10}\]from the surface of the earth is (Here R is the radius of the earth) (a) \[\frac{121g}{100}\]                 (b) \[\frac{100g}{121}\] (c) \[\frac{100g}{121}\]                  (d) \[\frac{121}{100g}\]

Answer:

\[g'=\frac{g{{R}^{2}}}{{{(R+h)}^{2}}}=\frac{g{{R}^{2}}}{{{\left( R+\frac{R}{10} \right)}^{2}}}=\frac{100g}{121{{R}^{2}}}=\frac{100g}{121}\]