question_answer

Find the force of gravitational attraction between two neutrons whose centres are 10-12 m apart. Given\[G=6.67\times {{10}^{-11}}N{{m}^{2}}k{{g}^{2}}\], mass of neutron\[=1.67\times {{10}^{-27}}kg\]. (a) \[1.8\times {{10}^{-42}}N\]                   (b) \[1.8\times {{10}^{-29}}N\] (c) \[1.8\times {{10}^{-40}}N\]                   (d) \[1.07\times {{10}^{-13}}N\]

Answer:

\[{{m}_{1}}={{m}_{2}}=1.67\times {{10}^{-27}}kg;\] \[r={{10}^{-12}}m\] \[G=6.67\times {{10}^{-11}}N{{m}^{2}}k{{g}^{-2}}\] \[F=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}=\frac{6.67\times {{10}^{11}}\times {{(1.67\times {{10}^{-27}})}^{2}}}{{{({{10}^{-12}})}^{2}}}\]