A) \[9.2\times {{10}^{-7}}N{{m}^{2}}k{{g}^{-2}}\]
B) \[6.13\times {{10}^{-11}}N{{m}^{2}}k{{g}^{-2}}\]
C) \[6.53\times {{10}^{-18}}N{{m}^{2}}k{{g}^{-2}}\]
D) \[6.53\times {{10}^{-11}}N{{m}^{2}}k{{g}^{-2}}\]
Correct Answer: D
Solution :
We know that, \[F=G\frac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\,or\,\,G=\frac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}}\] Given, \[F=9.8\times {{10}^{-7}}N,\,\,r=0.2\,\,m,\] \[{{m}_{1}}=40kg,\,\,{{m}_{2}}=15\,kg\] \[\therefore \,\,G=\frac{9.8\times {{10}^{-7}}\times {{(0.2)}^{2}}}{40\times 15}=6.53\times {{10}^{-11}}N{{m}^{2}}k{{g}^{-2}}\]You need to login to perform this action.
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