A) \[\frac{3}{2}\]
B) \[\frac{2}{3}\]
C) \[\frac{64}{81}\]
D) \[\frac{1}{2}\]
Correct Answer: C
Solution :
\[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{g}_{1}}}{{{g}_{2}}}\] \[{{g}_{1}}=\frac{g{{R}^{2}}}{{{\left( R+\frac{R}{2} \right)}^{2}}};\,\,{{g}_{2}}=\frac{g{{R}^{2}}}{{{\left( R+\frac{R}{3} \right)}^{2}}}\] \[\therefore \frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{\left( R+\frac{R}{3} \right)}^{2}}}{{{\left( R+\frac{R}{3} \right)}^{2}}}=\frac{\frac{16}{9}}{\frac{9}{4}}=\frac{64}{81}\]You need to login to perform this action.
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