A) \[\frac{R}{2}\]
B) \[(\sqrt{2}-1)R\]
C) \[R/\sqrt{2}\]
D) \[\frac{121R}{100}\]
Correct Answer: B
Solution :
\[{{g}_{1}}\frac{g{{R}^{2}}}{{{(R+h)}^{2}}}\Rightarrow \frac{g}{2}=\frac{g{{R}^{2}}}{{{(R+h)}^{2}}}\] \[\Rightarrow \frac{1}{\sqrt{2}}=\frac{R}{R+h}\Rightarrow R+h=\sqrt{2}R\,\,or\,h=(\sqrt{2}-1)R\]You need to login to perform this action.
You will be redirected in
3 sec