A) \[\text{6}.\text{67}\times \text{1}{{0}^{-\text{11}}}\text{ N}\]
B) \[\text{6}.\text{67}\times \text{1}{{0}^{-\text{9}}}\text{ N}\]
C) 6.67 N
D) \[\text{6}.\text{67}\times \text{1}{{0}^{-4}}\text{ N}\]
Correct Answer: A
Solution :
\[F=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\frac{6.67\times {{10}^{-11}}\times 100\times 100}{{{10}^{2}}}\] \[=6.67\times {{10}^{-11}}N\]
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