question_answer

A balloon is ascending with a uniform velocity of 15 m/s. A body falls out of it when it is at a height of 50 m from the ground. What is the time taken by the body to reach the ground? [Take\[\text{g}=\text{1}0\text{ m}/{{\text{s}}^{\text{2}}}\]]

Answer:

\[-h=ut-\frac{1}{2}g{{t}^{2}}\] Hence \[-50=15\times t-\frac{1}{2}\times 10{{t}^{2}}\] \[5{{t}^{2}}-15t-50=0\,\,or\,\,{{t}^{2}}-3t-10=0\] \[\therefore \,\,(t=5)(t+2)=0\,\,or\,\,t=5s\]