question_answer

A ball is thrown vertically upwards. It returns 6 seconds later. What is the greatest height reached by ball is ____ (\[\text{g}=\text{1}0\text{m}{{\text{s}}^{-\text{2}}}\]).

Answer:

Time of flight \[(T)=6s\] Maximum height \[(h)=?\] \[h=\frac{{{u}^{2}}}{2g}\] ?????.(1) Let us find u \[T=\frac{2u}{g}\Rightarrow u=30\,m/s\] Substituting in (1), we get\[h=\frac{30\times 30}{2\times 10}=45m\]