Answer:
Distance covered by first body in 3s \[=\frac{1}{2}\times 9.8\times {{(3)}^{2}}=44.1\,m\] Distance covered by second body in 2s \[=\frac{1}{2}\times 9.8\times {{(2)}^{2}}=19.6\,\,m\] Separation of two bodies 2 seconds after the release of second body \[=44.1-19.6=24.5\,m\]
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