A) \[\text{19}.\text{6 m}/{{\text{s}}^{\text{2}}}\]
B) \[\text{9}.\text{8 m}/{{\text{s}}^{\text{2}}}\]
C) \[\text{4}.\text{9 m}/{{\text{s}}^{\text{2}}}\]
D) \[\text{2}.\text{45 m}/{{\text{s}}^{\text{2}}}\]
Correct Answer: D
Solution :
From relation, \[g=\frac{GM}{{{r}^{2}}}\] Here, \[r=R+R=2R\] Hence, \[g=\frac{GM}{{{(2R)}^{2}}}=\frac{GM}{4{{R}^{2}}}=\frac{1}{4}\left( \frac{GM}{{{R}^{2}}} \right)=\frac{9.8}{4}=2.45\] \[\therefore g=2.45\,\,m/{{s}^{2}}\]You need to login to perform this action.
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