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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Graphical Questions

  • question_answer
    Radioactive element decays to form a stable nuclide, then the rate of decay of reactant \[\left( \frac{dN}{dt} \right)\] will vary with time (t) as shown in figure                                                                       [DCE 2000]

    A)                        

    B)                   

    C)                      

    D)                

    Correct Answer: C

    Solution :

                       \[N={{N}_{0}}{{e}^{-\lambda t}}\]Þ \[\frac{dN}{dt}=-{{N}_{0}}\lambda {{e}^{-\lambda t}}\] i.e. Rate of decay \[\left( \frac{dN}{dt} \right)\] varies exponentially with time (t).


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