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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Graphical Questions

  • question_answer
    An alternating current of frequency 200 rad/sec and peak value 1A as shown in the figure, is applied to the primary of a transformer. If the coefficient of mutual induction between the primary and the secondary is 1.5 H, the voltage induced in the secondary will be

    A)            300 V

    B)            191 V

    C)            220 V

    D)            471 V

    Correct Answer: B

    Solution :

                       \[e=-M\frac{di}{dt}=-1.5\frac{(1-0)}{(T/4)}=-\frac{6}{T}\], \[T=\frac{2\pi }{\omega }=\frac{2\pi }{200}=\frac{\pi }{100}\]            Þ\[\,|e|\,=\frac{600}{\pi }=190.9\,V\tilde{}\,191V\]


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