A)
B)
C)
D)
Correct Answer: C
Solution :
For hollow sphere \[{{V}_{in}}=\frac{-GM}{R}\],\[{{V}_{\text{surface}}}=\frac{-GM}{R},{{V}_{out}}=\frac{-GM}{r}\] i.e. potential remain constant inside the sphere and it is equal to potential at the surface and increase when the point moves away from the surface of sphere.
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