A) \[{{f}_{a}}={{f}_{b}}\] and \[{{l}_{a}}\ne {{l}_{b}}\]
B) \[{{f}_{a}}={{f}_{c}}\] and \[{{l}_{a}}={{l}_{c}}\]
C) \[{{f}_{a}}={{f}_{b}}\] and \[{{l}_{a}}={{l}_{b}}\]
D) \[{{f}_{a}}={{f}_{b}}\] and \[{{l}_{a}}={{l}_{b}}\]
Correct Answer: A
Solution :
The stopping potential for curves a and b is same. \ \[{{f}_{a}}={{f}_{b}}\] Also saturation current is proportional to intensity \ \[{{I}_{a}}<{{I}_{b}}\]You need to login to perform this action.
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