The most probable velocity-time graph of the body is
A)
B)
C)
D)
Correct Answer: C
Solution :
From given \[a-t\] graph it is clear that acceleration is increasing at constant rate \[\therefore \] \[\frac{da}{dt}=k\] (constant) Þ \[a=kt\] (by integration) Þ \[\frac{dv}{dt}=kt\] Þ \[dv=ktdt\] Þ \[\int_{{}}^{{}}{dv}=k\int_{{}}^{{}}{tdt}\]Þ\[v=\frac{k{{t}^{2}}}{2}\] i.e. v is dependent on time parabolically and parabola is symmetric about v-axis and suddenly acceleration becomes zero. i.e. velocity becomes constant. Hence is most probable graph.
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