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JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Graphical Questions

  • question_answer
    In the graph given below. If the slope is \[4.12\times {{10}^{-15}}\]V-sec, then value of ?h? should be

    A)            \[6.6\times {{10}^{-31}}\] J-sec

    B)            \[6.6\times {{10}^{-34}}\]J-sec

    C)            \[9.1\times 10-31\] J-sec

    D)            None of these

    Correct Answer: B

    Solution :

                       Slope of \[{{V}_{0}}-\nu \] curve \[=\frac{h}{e}\]                    Þ h = Slope ´ e = 1.6 ´ 10?19´ 4.12 ´ 10?15             \[=6.6\times {{10}^{-34}}\,J\text{-}\sec \].


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