A)
B)
C)
D)
Correct Answer: A
Solution :
Given line have positive intercept but negative slope. So its equation can be written as \[v=-mx+{{v}_{0}}\] ?..(i) [where \[m=\tan \theta =\frac{{{v}_{0}}}{{{x}_{0}}}\]] By differentiating with respect to time we get \[\frac{dv}{dt}=-m\frac{dx}{dt}=-mv\] Now substituting the value of v from eq. (i) we get \[\frac{dv}{dt}=-m[-mx+{{v}_{0}}]={{m}^{2}}x-m{{v}_{0}}\] \ \[a={{m}^{2}}x-m{{v}_{0}}\] i.e. the graph between a and x should have positive slope but negative intercept on a-axis. So graph is correct.
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