A) A
B) B
C) C
D) None of the above
Correct Answer: A
Solution :
\[{{K}_{\max }}=h\nu -h{{\nu }_{0}}=\frac{hc}{\lambda }-\frac{hc}{{{\lambda }_{0}}}\] i.e. graph between \[{{K}_{\max }}\] and \[\frac{1}{\lambda }\] will be straight line having slope (hc) and intercept \[\frac{hc}{{{\lambda }_{0}}}\] on ? KE axis.
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