A) V1 > V2, Z1 < Z2
B) V1 > V2, Z1 > Z2
C) V1 < V2, Z1 > Z2
D) V1 = V2, Z1 < Z2
Correct Answer: A
Solution :
\[{{\lambda }_{\min }}=\frac{hc}{eV}\] Þ\[\lambda \propto \frac{1}{V}\] \[\because \ {{\lambda }_{2}}>{{\lambda }_{1}}\] (see graph) Þ\[{{V}_{1}}>{{V}_{2}}\] \[\sqrt{\nu }=a(Z-b)\] Moseley?s law \[\nu \propto {{(Z-1)}^{2}}\]Þ \[\lambda \propto \frac{1}{{{(Z-1)}^{2}}}\] \[\left( \because \ \nu \propto \frac{1}{\lambda } \right)\] \[{{\lambda }_{1}}>{{\lambda }_{2}}\] (see graph for characteristic lines) Þ\[{{Z}_{2}}>{{Z}_{1}}\].
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