A) 4
B) 3
C) 2
D) 1
Correct Answer: A
Solution :
\[{{A}_{n}}=\pi r_{n}^{2}\]Þ \[\frac{{{A}_{n}}}{{{A}_{1}}}={{\left( \frac{{{r}_{n}}}{{{r}_{1}}} \right)}^{2}}={{\left( \frac{n}{1} \right)}^{4}}\] \[(\because {{r}_{n}}\propto {{n}^{2}})\] Taking loge both the side \[{{\log }_{e}}\frac{{{A}_{n}}}{{{A}_{1}}}=4\,{{\log }_{e}}(n)\] Comparing it with y = mx + c, graph (4) is correct.You need to login to perform this action.
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