A) Is the same for all metals and independent of the intensity of the radiation
B) Depends on the intensity of the radiation
C) Depends both on the intensity of the radiation and the metal used
D) Depends on the nature of the metals used
Correct Answer: A
Solution :
\[h\nu =h{{\nu }_{0}}+K{{E}_{\max }}\] Þ \[K{{E}_{\max }}=h\nu -h{{\nu }_{0}}\] On comparing this equation with \[y=mx+c\] we get \[m=h=\]Universal constant
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