A)
B)
C)
D)
Correct Answer: C
Solution :
When loop is entering in the field, magnetic flux (i.e. ´) linked with the loop increases so induced emf in it \[e=Bvl\]=\[0.6\times {{10}^{-2}}\times 5\times {{10}^{-2}}=3\times {{10}^{-4}}V\] (Negative) . When loop completely entered in the field (after 5 sec) flux linked with the loop remains constant so e = 0. After 15 sec, loop begins to exit out, linked magnetic flux decreases so induced emf \[e=3\times {{10}^{-4}}V\] (Positive).
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