2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Semiconducting Devices

JEE Main & Advanced Physics Semiconducting Devices Question Bank Graphical Questions

  • question_answer
    For a thermionic emitter (metallic) if J represents the current density and T is its absolute temperature then the correct curve between \[{{\log }_{e}}\frac{J}{{{T}^{2}}}\] and \[\frac{1}{T}\] is

    A)

    B)                             

    C)                                     

    D)                             

    Correct Answer: A

    Solution :

                       According to Richardson-Dushman equation \[J=A{{T}^{2}}{{e}^{-b/T}}\] Taking log of this equation \[{{\log }_{e}}\frac{J}{{{T}^{2}}}={{\log }_{e}}A-\frac{b}{T}\] i.e. graph between \[{{\log }_{e}}\frac{J}{{{T}^{2}}}\] and \[\frac{1}{T}\] will be a straight line having negative slope and positive intercept (logeA) on \[{{\log }_{e}}\frac{J}{{{T}^{2}}}\text{axis}\text{.}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner