JEE Main & Advanced Physics Elasticity Question Bank Graphical Questions

  • question_answer
    The value of force constant between the applied elastic force F and displacement will be

    A)             \[\sqrt{3}\]

    B)             \[\frac{1}{\sqrt{3}}\]

    C)             \[\frac{1}{2}\]

    D)             \[\frac{\sqrt{3}}{2}\]

    Correct Answer: B

    Solution :

                    Force constant, K = tan 30° = \[1/\sqrt{3}\]


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