JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Graphical Questions

  • question_answer
    If in hydrogen atom, radius of \[{{n}^{th}}\] Bohr orbit is \[{{r}_{n}},\] frequency of revolution of electron in \[{{n}^{th}}\] orbit is \[{{f}_{n}}\] choose the correct option 

    A)                                   

    B)                 

    C)                         

    D)            Both (a) and (b)

    Correct Answer: D

    Solution :

                       Radius of nth orbit \[{{r}_{n}}\propto {{n}^{2}}\], graph between rn and n is a parabola. Also, \[\frac{{{r}_{n}}}{{{r}_{1}}}={{\left( \frac{n}{1} \right)}^{2}}\Rightarrow {{\log }_{e}}\left( \frac{{{r}_{n}}}{{{r}_{1}}} \right)=2{{\log }_{e}}(n)\] Comparing this equation with y = mx + c, Graph between \[{{\log }_{e}}\left( \frac{{{r}_{n}}}{{{r}_{1}}} \right)\] and \[{{\log }_{e}}(n)\] will be a straight line, passing from origin. Similarly it can be proved that graph between \[{{\log }_{e}}\left( \frac{{{f}_{n}}}{{{f}_{1}}} \right)\] and loge n is not a straight line.


You need to login to perform this action.
You will be redirected in 3 sec spinner