A)
B)
C)
D)
Correct Answer: C
Solution :
\[U=\frac{-GMm}{r},K=\frac{GMm}{2r}\] and \[E=\frac{-GMm}{2r}\] For a satellite U,K and E varies with r and also U and E remains negative whereas K remain always positive.You need to login to perform this action.
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