A) I, II and III
B) II only
C) I and III
D) III only
Correct Answer: C
Solution :
Speed = \[n\lambda \]= \[n(4ab)=4n\times ab\] \[\left( \text{As}\,ab=\frac{\lambda }{4} \right)\] Path difference between \[b\] and \[e\] is \[\frac{3\lambda }{4}\] So the phase difference =\[\frac{2\pi }{\lambda }\]. Path difference = \[\frac{2\pi }{\lambda }.\frac{3\lambda }{4}=\frac{3\pi }{2}\]You need to login to perform this action.
You will be redirected in
3 sec