question_answer

Two base angles of a triangle ABC are bisected and meet at P. What is the measure of angle BPC if\[{{50}^{o}}\] and\[{{120}^{o}}\].

A)  \[\angle A={{80}^{o}}\]                            

B)  \[\angle C={{35}^{o}}\]

C)  \[\angle EDB=\]                     

D)  \[{{120}^{o}}\]

Correct Answer: D

Solution :

Given \[\angle ACB=\angle ADB\] and \[{{65}^{o}}\] Now, \[{{85}^{o}}\] and \[{{30}^{o}}\] are bisected \[{{45}^{o}}\] \[{{60}^{o}}\] and  \[{{90}^{o}}\] Find \[\angle x\] \[{{80}^{o}}\] (Sum of angles of \[{{70}^{o}}\] is \[{{60}^{o}}\]) \[{{110}^{o}}\] \[\Delta ABC\] \[{{180}^{o}}\]