6th Class Mathematics Practical Geometry Question Bank Geometry

  • question_answer
    DIRECTIONS: Match Column-I with Column-II and select the correct answer using the codes given below the columns.  

    A)  \[A\to (iii),\,B\to (v);\,C\to (iv);\,D\to (i);\,E\to (vi);\,F\to (ii)\]

    B) \[A\to (iv),\,B\to (v);\,C\to (vi);\,D\to (i);\,E\to (ii);\,F\to (iii)\]

    C) \[A\to (iv),\,B\to (ii);\,C\to (iii);\,D\to (i);\,E\to (v);\,F\to (vi)\]

    D)  \[A\to (iii),\,B\to (iv);\,C\to (v);\,D\to (vi);\,E\to (i);\,F\to (ii)\]

    Correct Answer: D

    Solution :

         D. Given: \[{{90}^{\text{o}}}\times \frac{5}{6}\,=15\times 5={{75}^{\text{o}}}\] \[\therefore \]  Required supplement\[~=\text{ }180\text{ }-\text{ }75\text{ }=\text{ }105{}^\circ \] (F) let the angle be \['\theta '\]. Given: \[({{180}^{\text{o}}}-\theta )\,-(\theta )\,={{36}^{\text{o}}}\] \[\Rightarrow \,\,\,180\,-36=2\theta =\theta ={{72}^{\text{o}}}\] \[\therefore \]  Required angle \[=180{}^\circ \text{ }-\text{ }72{}^\circ \text{ }=\text{ }108{}^\circ \]


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