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6th Class Mathematics Practical Geometry Question Bank Geometry

  • question_answer
    In \[\Delta ABC,\] \[\angle A=30{}^\circ ,\]\[\angle C=120{}^\circ ,\]BE is parallel to BC and\[x{}^\circ =y{}^\circ ,x{}^\circ +y{}^\circ +z{}^\circ =?\]

    A) \[180{}^\circ \]                                 

    B)  \[210{}^\circ \]

    C) \[150{}^\circ \]                                 

    D)  \[90{}^\circ \]

    Correct Answer: A

    Solution :

    In \[\Delta ABC\] \[\angle A+\angle B+\angle C=180{}^\circ \] \[30{}^\circ +x{}^\circ +120{}^\circ =180{}^\circ \] \[x=130{}^\circ \] \[x=y=30{}^\circ \] Now, in \[\Delta ADE\] \[30{}^\circ +y+z=180{}^\circ \] \[z=120{}^\circ \] \[\therefore \]\[x+y+z=30{}^\circ +30{}^\circ +120{}^\circ =180{}^\circ \]


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