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8th Class Mathematics Practical Geometry Question Bank Geometry

  • question_answer
    In the figure \[{{240}^{o}}\] \[\angle C={{30}^{o}}\] is equal to

    A)  \[\angle A\]                             

    B)  \[\angle B\]

    C)  \[{{60}^{o}}\]                    

    D)  \[{{90}^{o}}\]

    Correct Answer: C

    Solution :

    \[{{50}^{o}}\] Since, the transversal BE intersects two parallel lines AB and CD. \[{{60}^{o}}\] \[\angle BAD={{120}^{o}}\] \[\angle BCD\] (\[{{240}^{o}}\] is exterior angle of \[{{60}^{o}}\]) \[{{120}^{o}}\] \[{{180}^{o}}\] \[\angle R={{138}^{o}}\] i.e., \[\angle PQS\]      


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