JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Geometry of complex numbers

  • question_answer
    If \[|z-2-3i|+|z+2-6i|=4\], where \[i=\sqrt{-1}\], then locus of \[P(z)\] is [DCE 2005]

    A) An ellipse

    B) \[\varphi \]

    C) Line segment joining of point \[2+3i\] and \[-2+6i\]

    D) None of these

    Correct Answer: B

    Solution :

    \[|z-{{z}_{1}}|+|z-{{z}_{2}}|=2a\] when \[|{{z}_{1}}-{{z}_{2}}|\le 2a\], then it is an ellipse \[{{z}_{1}}=2+3i\] and \[{{z}_{2}}=-2+6i\] \[{{z}_{1}}-{{z}_{2}}=(2+3i)-(-2+6i)=4-3i\] \[|{{z}_{1}}-{{z}_{2}}|=|4-3i|\]  = \[\sqrt{{{4}^{2}}+{{(-3)}^{2}}}=5\] But \[5<4\] is false, because in any triangle sum of two sides is not smaller than third side. \[\therefore \] \[P(z)\] is not represent locus of any point.


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