JEE Main & Advanced Mathematics Sequence & Series Question Bank Geometric Progression

  • question_answer
    If the nth term of geometric progression \[5,-\frac{5}{2},\frac{5}{4},-\frac{5}{8},...\] is \[\frac{5}{1024}\], then the value of n is [Kerala (Engg.) 2002]

    A) 11

    B) 10

    C) 9

    D) 4

    Correct Answer: A

    Solution :

    \[\frac{448r-7}{r-1}=889\] Þ \[\frac{b}{a},\frac{c}{b},\frac{a}{c}\] Þ \[{{\left( \frac{-1}{2} \right)}^{10}}={{\left( \frac{-1}{2} \right)}^{n-1}}\]Þ \[10=n-1\]Þ \[n=11\].


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