A) \[CH\equiv CH\]
B) \[C{{H}_{2}}=C{{H}_{2}}\]
C) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
D) \[C{{H}_{3}}-C\equiv CH\]
Correct Answer: C
Solution :
\[\underset{\text{Propene}}{\mathop{nC{{H}_{3}}}}\,CH=C{{H}_{2}}\to \underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{Polypropylene}}{\mathop{{{(-\,C{{H}_{2}}-\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{CH-}}\,}}\,)}_{n}}}}\,\]
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