A) \[{{C}_{9}}{{H}_{18}}{{O}_{9}}\]
B) \[C{{H}_{2}}O\]
C) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
D) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]
Correct Answer: C
Solution :
\[n=\frac{180}{MolecularmassofC{{H}_{2}}O}=\frac{180}{30}\]\[n=6\]
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