JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{\frac{dx}{\sqrt{{{x}^{2}}+{{a}^{2}}}}}\] is equal to                                [MP PET 2004]

    A)            \[\frac{1}{2}x\sqrt{{{x}^{2}}+{{a}^{2}}}+\frac{1}{2}{{a}^{2}}\log (x+\sqrt{{{x}^{2}}+{{a}^{2}}})+c\]       

    B)            \[\frac{1}{2}\log ({{x}^{2}}+{{a}^{2}})+c\]

    C)            \[\log (x+\sqrt{{{x}^{2}}+{{a}^{2}}})+c\]

    D)            \[\log (x-\sqrt{{{x}^{2}}+{{a}^{2}}})+c\]

    Correct Answer: C

    Solution :

               It is a fundamental concept.


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