A) \[3\cot x+\frac{2}{3}\cos 3x+c\]
B) \[-\left( 3\cot x+\frac{2}{3}\cos 3x \right)+c\]
C) \[3\cot x-\frac{2}{3}\cos 3x+c\]
D) None of these
Correct Answer: B
Solution :
\[\int_{{}}^{{}}{(3\text{cose}{{\text{c}}^{\text{2}}}x+2\sin 3x)\,dx}\] \[=-3\cot x-\frac{2\cos 3x}{3}+c=-\,[3\cot x+\frac{2}{3}\cos 3x]+c.\]You need to login to perform this action.
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