A) \[{{x}^{3}}+5x-1\]
B) \[{{x}^{3}}+5x+1\]
C) \[\frac{1}{3}{{x}^{3}}+5x-1\]
D) \[\frac{1}{3}{{x}^{3}}+5x+1\]
Correct Answer: C
Solution :
Given that \[{f}'(x)={{x}^{2}}+5\] and \[f(0)=-1\] Þ \[f(x)=\frac{{{x}^{3}}}{3}+5x+c\]. If \[x=0,\] then \[f(0)=c\]Þ \[c=-1\]. Hence \[f(x)=\frac{{{x}^{3}}}{3}+5x-1.\]You need to login to perform this action.
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