A) \[{{\cos }^{-1}}x+c\]
B) \[{{\sec }^{-1}}x+c\]
C) \[{{\cot }^{-1}}x+c\]
D) \[{{\tan }^{-1}}x+c\]
Correct Answer: B
Solution :
\[\int_{{}}^{{}}{\frac{1}{x\sqrt{{{x}^{2}}-1}}\,dx={{\sec }^{-1}}x+c}\] (formula).
You need to login to perform this action.
You will be redirected in
3 sec
