JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Fundamental Integration

  • question_answer
    \[\int_{{}}^{{}}{{{\left( x+\frac{1}{x} \right)}^{3}}}dx=\]

    A)            \[\frac{1}{4}{{\left( x+\frac{1}{x} \right)}^{4}}+c\]                     

    B)            \[\frac{{{x}^{4}}}{4}+\frac{3{{x}^{2}}}{2}+3\log x-\frac{1}{2{{x}^{2}}}+c\]

    C)            \[\frac{{{x}^{4}}}{4}+\frac{3{{x}^{2}}}{2}+3\log x+\frac{1}{{{x}^{2}}}+c\]

    D)            None of these

    Correct Answer: B

    Solution :

               \[\int_{{}}^{{}}{{{\left( x+\frac{1}{x} \right)}^{3}}dx=\int_{{}}^{{}}{\left( {{x}^{3}}+\frac{1}{{{x}^{3}}}+3x+\frac{3}{x} \right)\,dx}}\]                                 \[=\frac{{{x}^{4}}}{4}-\frac{1}{2{{x}^{2}}}+\frac{3{{x}^{2}}}{2}+3\log x+c\]                                                               \[=\frac{{{x}^{4}}}{4}+\frac{3{{x}^{2}}}{2}+3\log x-\frac{1}{2{{x}^{2}}}+c.\]


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