A) \[e-2\]
B) \[e+2\]
C) \[{{e}^{2}}-2\]
D) \[{{e}^{2}}\]
Correct Answer: A
Solution :
We have, \[I=\int_{0}^{1}{{{x}^{2}}{{e}^{x}}dx}\]Þ \[I=[{{x}^{2}}.{{e}^{x}}]_{0}^{1}-\int_{0}^{1}{2x.{{e}^{x}}dx}\] Þ \[I=e-2[x{{e}^{x}}-{{e}^{x}}]_{0}^{1}\]Þ\[I=e-2\,[e-e-(0-1)]\] Þ \[I=e-2\].You need to login to perform this action.
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