A) \[0\]
B) 1
C) \[e-1\]
D) \[e+1\]
Correct Answer: B
Solution :
\[I=\int_{1}^{e}{\,\log x\,dx}\]Þ \[I=\int_{e}^{1}{\,1.\log x\,dx}\] Þ \[I=[x\log x-x]_{1}^{e}=(e\log e-e)-(0-1)\] Þ \[I=1\].You need to login to perform this action.
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