JEE Main & Advanced Mathematics Functions Question Bank Functions

  • question_answer
    The range of \[f(x)=\cos 2x-\sin 2x\] contains the set [IIT Screening]

    A)                    [2, 4]

    B)            [?1, 1]

    C)            [?2, 2]

    D)            [?4, 4]

    Correct Answer: B

    Solution :

               \[f(x)=\sqrt{2}\,\left[ \sin \left( \frac{\pi }{4}-2x \right) \right]\]                    \[\therefore \,\,-\sqrt{2}\le f(x)\le \sqrt{2}\] and \[[-1,\,\,1]\,\subset \,[-\sqrt{2},\sqrt{2}]\].


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