JEE Main & Advanced Mathematics Functions Question Bank Functions

  • question_answer
    The range of \[f(x)=\cos x-\sin x\] is            [MP PET 1995; Pb. CET 2001]           

    A)            \[(-1,\ 1)\]

    B)             \[[-1,\,\ 1)\]

    C)            \[\left[ -\frac{\pi }{2},\ \frac{\pi }{2} \right]\]

    D)            \[[-\sqrt{2},\ \sqrt{2}]\]

    Correct Answer: D

    Solution :

               Since maximum and minimum values of \[\cos x-\sin x\] are \[\sqrt{2}\] and \[-\sqrt{2}\] respectively, therefore range of \[f(x)\] is \[[-\sqrt{2},\,\,\sqrt{2}].\]


You need to login to perform this action.
You will be redirected in 3 sec spinner