JEE Main & Advanced Mathematics Functions Question Bank Functions

  • question_answer
    Domain of \[f(x)={{({{x}^{2}}-1)}^{-1/2}}\] is [Roorkee 1987]           

    A)            \[(-\infty ,\ -1)\cup (1,\ \infty )\]

    B)             \[(-\infty ,\ -1]\cup (1,\ \infty )\]

    C)            \[(-\infty ,\ -1]\cup [1,\ \infty )\]

    D)            None of these

    Correct Answer: A

    Solution :

               Here \[|x|\,\,>1,\] therefore \[x\in (-\,\infty ,\,-1)\,\cup \,(1,\,\,\infty ).\]


You need to login to perform this action.
You will be redirected in 3 sec spinner